foreach should return the same enumerable
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@@ -111,18 +111,19 @@ namespace System.Linq
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}
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}
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public static void ForEach<T>(this IEnumerable<T> source, Action<T> action)
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public static IEnumerable<T> ForEach<T>(this IEnumerable<T> source, Action<T> action)
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{
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Enumerate(source, action);
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return Enumerate(source, action);
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}
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public static void ForEach<T>(this IEnumerable<T> source, Action<T, int> action)
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public static IEnumerable<T> ForEach<T>(this IEnumerable<T> source, Action<T, int> action)
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{
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var index = 0;
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var enumerator = source.GetEnumerator();
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while(enumerator.MoveNext())
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{
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action?.Invoke(enumerator.Current, index);
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yield return enumerator.Current;
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index++;
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}
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}
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@@ -141,12 +142,13 @@ namespace System.Linq
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}
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}
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private static void Enumerate<T>(IEnumerable<T> source, Action<T> action)
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private static IEnumerable<T> Enumerate<T>(IEnumerable<T> source, Action<T> action)
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{
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var enumerator = source.GetEnumerator();
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while(enumerator.MoveNext())
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{
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action?.Invoke(enumerator.Current);
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yield return enumerator.Current;
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}
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}
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}
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